题解 | #牛牛的digit#
牛牛的digit
https://www.nowcoder.com/practice/21b49f1f495f4280b8a96c415deaa3c4
#include<stdio.h>
int digit(int x,int i)
{
if(i==0)
{
return 0;
}
else
return digit(x/10,i-1)*10+x%10;
}
int main()
{
int x,i;
scanf("%d %d",&x,&i);
printf("%d",digit(x,i));
return 0;
}
