题解 | #学英语#
学英语
https://www.nowcoder.com/practice/1364723563ab43c99f3d38b5abef83bc
考虑到三位一循环的结构，采取递归方法，希望用‘ ’.join()来输出结果，但是实际上输出时会出现格式错
遂借助split替换重复空格
num1 = ['','one','two','three','four','five','six',
'seven','eight','nine','ten','eleven','twelve',
'thirteen','fourteen','fifteen','sixteen',
'seventeen','eighteen','nineteen']
num2 = ['','','twenty','thirty','forty','fifty','sixty',
'seventy','eighty','ninety']
def word(n):
if n<20:
return [num1[n]]
if n<100:
return [num2[n//10]] + [num1[n%10]]
if n<1000:
if n%100==0:
return [num1[n//100]] + ['hundred']
else:
return [num1[n//100]] + ['hundred and'] + word(n%100)
for p,w in enumerate(['thousand','million','billion']):
if n<1000**(p+2):
return word(n//1000**(p+1)) + [w] + word(n%1000**(p+1))
while True:
try:
num = int(input())
if num == 0 :
print('zero')
else:
print(' '.join((' '.join(word(num))).split()))
except:
break
