题解 | #验证IP地址#
验证IP地址
https://www.nowcoder.com/practice/55fb3c68d08d46119f76ae2df7566880
需要考虑的场景比较多；
本人将ipv4与ipv6分开考虑处理；
用split('.')将字符串转化成列表进行判断
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 验证IP地址
# @param IP string字符串 一个IP地址字符串
# @return string字符串
#
class Solution:
def solve(self , IP: str) -> str:
# write code here
# 构造一个16进制的字符串备用
v6 = '0123456789abcdef'
if IP.count('.') >0 and IP.count(':')>0:
return 'Neither'
elif IP.count('.') >0 and not IP.count(':'):
IPv4 = IP.split('.')
# print(IPv4)
if len(IPv4) != 4:
return 'Neither'
else:
if IPv4[0] == '0':
return 'Neither'
else:
for i in IPv4:
if not i.isnumeric():
return 'Neither'
if not i :
return 'Neither'
if int(i) < 0 or int(i) > 255:
return 'Neither'
else:
if len(i) > 1 and i[0] == '0':
return 'Neither'
# else:
return 'IPv4'
elif not IP.count('.') and IP.count(':') > 0:
if len(IP) > 50:
return 'Neither'
IP = IP.lower()
IPv6 = IP.split(':')
if len(IPv6) != 8:
return 'Neither'
else:
for i in IPv6:
if not i:
return 'Neither'
for j in i:
if j not in v6:
return 'Neither'
if len(i) > 1 and i[0] == '0' and i[1] == '0':
return 'Neither'
return 'IPv6'
else:
return 'Neither'
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