题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
#代码的魅力在于简洁即优雅
a=[[1,2,3],[4,5,6],[7,8,9]]
n=int(input())
for x in range(len(a)):
for y in range(len(a[x])):
a[x][y]=a[x][y]*n
print(a)
a=[[1,2,3],[4,5,6],[7,8,9]]
n=int(input())
for x in range(len(a)):
for y in range(len(a[x])):
a[x][y]=a[x][y]*n
print(a)
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