题解 | #牛牛的计划#
牛牛的计划
https://www.nowcoder.com/practice/cf956ceef9f84f7393a0b7284fdbf95a
# include <stdio.h>
int main(){
int y,m,d;
int y1,m1,d1;
scanf("%d %d %d \n %d %d %d",&y,&m,&d,&y1,&m1,&d1);
if ((y*10000+m*100+d) <= (y1*10000+m1*100+d1))
printf("yes");
else
printf("no");
return 0;
}
”
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