题解 | #获得月份天数#
获得月份天数
https://www.nowcoder.com/practice/13aeae34f8ed4697960f7cfc80f9f7f6
#include<stdio.h>
int main()
{
int year = 0;//输入的年分
int month = 0;//输入的月份
int x = 0;//该月天数
while(scanf("%d %d",&year,&month )!= EOF)
{
switch(month){
case 1 : x = 31;
break;
case 2 : x = 28;
break;
case 3: x = 31;
break;
case 4: x = 30;
break;
case 5: x = 31;
break;
case 6: x = 30;
break;
case 7: x = 31;
break;
case 8: x = 31;
break;
case 9: x = 30;
break;
case 10: x = 31;
break;
case 11: x = 30;
break;
case 12: x = 31;
break;
}
if((year%4==0 && year%100!=0)||year%400==0)//判断该年份是不是闰年。若是,则二月为29天,若不是,则二月为28天
if(month == 2)
x = 29;
printf("%d\n",x);
};
return 0;
}
