题解 | #删除链表的节点#

class Solution:
    def deleteNode(self , head: ListNode, val: int) -> ListNode:
        # write code here
        if head.val == val:
            head = head.next
        else:
            pre = head
            now = head
            while now:
                if now.val == val:
                    pre.next = now.next
                    break
                pre = now
                now = now.next
        return head