题解 | #坐标移动#
坐标移动
https://www.nowcoder.com/practice/119bcca3befb405fbe58abe9c532eb29
# A10;S20;W10;D30;X;A1A;B10A11;;A10;
s = input()
list_str = s.split(';')
x = 0
y = 0
direction_zy = {"A": -1, "D": 1}
direction_sx = {"W": 1, "S": -1}
direction = dict(direction_zy)
direction.update(direction_sx)
for i in range(len(list_str)-1):
str = list_str[i]
if len(str)==0 or len(str)>3:
continue
if str[0] not in direction.keys():
continue
try:
number = int(str[1:])
except:
number = -1
if number>=0:
if str[0] in direction_sx.keys():
y = y + direction[str[0]] * number
else:
x = x + direction[str[0]] * number
print(f'{x},{y}')
渣渣的写法,哈哈,打卡的第一题,留个笔#字节测试开发一面面经#