题解 | #矩阵乘法#
矩阵乘法
http://www.nowcoder.com/practice/ebe941260f8c4210aa8c17e99cbc663b
个人感觉华为的题库,中等题中部分题中规中矩
估计这些题侧重考察的是基础能力,这道题纯纯的按题目要求来即可;
感觉递归套两层循环应该也能做~
既然考察基础,就用暴力美学写一下吧【doge】
#include<iostream> #include<vector> using namespace std; int first_row;//第一个矩阵的行 int first_col;//第一个矩阵的列 int second_row;//第二个矩阵的行 int second_col;//第二个矩阵的列 void deal_fun(vector<vector<int>>&f_matrix,vector<vector<int>>&s_matrix,vector<vector<long int>>&result_matrix,int row) { int a = -1; while (a < second_col) { a++; if (a >= second_col)break; long int result = 0; for (int j = 0; j < first_col; j++) { result+= f_matrix[row][j] * s_matrix[j][a]; } result_matrix[row][a] = result; } } int main() { cin >> first_row >> first_col >> second_col; second_row = first_col; vector<vector<int>>f_matrix(first_row, vector<int>(first_col, 0)); vector<vector<int>>s_matrix(second_row, vector<int>(second_col, 0)); for (int i = 0; i < first_row; i++) { for (int j = 0; j < first_col; j++) cin >> f_matrix[i][j]; } for (int i = 0; i < second_row; i++) { for (int j = 0; j < second_col; j++) cin >> s_matrix[i][j]; } vector<vector<long int>>result_matrix(first_row, vector<long int>(second_col)); for (int i = 0; i < first_row; i++) { deal_fun(f_matrix, s_matrix, result_matrix, i); } for (int i = 0; i < first_row; i++) { for (int j = 0; j < second_col; j++) { cout << result_matrix[i][j] << " "; } cout << endl; } return 0; }