题解 | #链表内指定区间反转#
链表内指定区间反转
http://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param head ListNode类
# @param m int整型
# @param n int整型
# @return ListNode类
#
class Solution:
def reverseBetween(self , head: ListNode, m: int, n: int) -> ListNode:
# write code here
#加个表头
res = ListNode(-1)
res.next = head
#前序节点
pre = res
#当前节点
cur = head
#找到m
for i in range(1,m):
pre = cur
cur = cur.next
#从m反转到n
for i in range(m, n):
temp = cur.next
cur.next = temp.next
temp.next = pre.next
pre.next = temp
#返回去掉表头
return res.next