题解 | #计算糖果#

#include <iostream>
#include <algorithm>

using namespace std;

int main(){
    int a_b,b_c,ab,bc;
    cin>>a_b>>b_c>>ab>>bc;
    int sum = a_b + ab + bc + b_c;
    int a = (a_b + ab)/2;
    int b = (b_c + bc)/2;
    int c = bc - b;
    
    if(2*a + 2*b != sum || a < 0 || b < 0 || c < 0) cout<<"No";
    else cout<<a<<" "<<b<<" "<<c<<endl;
    
}