题解 | #跳台阶#
跳台阶
http://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
/*
动态规划：
dp[n] = dp[n-1] + dp[n-2]
*/
int jumpFloor(int number ) {
if(number<3) return number;
int n1 = 1;
int n2 = 2;
for(int i = 3; i<=number; i++){
int temp = n2;
n2 = n1+n2;
n1 = temp;
}
return n2;
}
中国联通工作强度 78人发布
