题解 | #从尾到头打印链表#

/*function ListNode(x){ this.val = x; this.next = null;

//指针如果时head，head.next指向下一个指针；head.val表示指针对应的值 }*/

 function printListFromTailToHead(head)

{

// write code here
var res = [];
while(head){

  res.unshift(head.val)
  head = head.next
  
 }

return res;

}

 module.exports = 

{

printListFromTailToHead : printListFromTailToHead

};