3.26 网易雷火笔试统计
1.统计。（简单遍历）
2.计算N张卡的得分。（模拟）
3.句子按行输出。（模拟，怎么感觉样例有问题,只过了48%。。）
4.海水上涨，到达目标岛屿至少等待时间。（bfs+优先队列，https://leetcode-cn.com/problems/swim-in-rising-water/）
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17:20更新
第一题 直接统计
#include <bits/stdc++.h>
using namespace std;
int a[101][101];
int main() {
int n, m;
cin >> n >> m;
int x, y;
cin >> x >> y;
int ans = 0;
for(int i = 0; i < n; i++) {
for(int j = 0; j < m; j++) {
cin >> a[i][j];
if(i == x - 1 && j == y - 1) continue;
ans += a[i][j];
}
}
cout << ans + 1 << endl;
return 0;
} #include <bits/stdc++.h>
using namespace std;
int main() {
int M;
cin >> M;
while(M--) {
int N;
cin >> N;
vector<int>a(N);
for(int i = 0; i < N; i++) {
cin >> a[i];
}
vector<char>b(N);
for(int i = 0; i < N; i++) {
cin >> b[i];
}
if(N == 5) {
bool flag = true;
for(int i = 0; i < N; i++) if(a[i] != a[0]) {
flag = false;
break;
}
if(flag) {
cout << 15000 << endl;
continue;
}
flag = true;
for(int i = 0; i < N; i++) if(b[i] != b[0]) {
flag = false;
break;
}
if(flag) {//lei bie xiang tong
sort(a.begin(), a.end());
for(int i = 1; i < N; i++) if(a[i] != a[i - 1] + 1) {
flag = false;
break;
}
if(flag) {
cout << 8000 << endl;
continue;
} else {
cout << 300 << endl;
continue;
}
}
}
unordered_map<int, int>mp;
for(int i = 0; i < N; i++) mp[a[i]]++;
int count1 = 0, count2 = 0, count3 = 0, count4 = 0, count5;
for(auto &[k, v]: mp) {
if(v == 5) {
count5++;
} else if(v == 4) {
count4++;
} else if(v == 3) {
count3++;
} else if(v == 2) {
count2++;
} else if(v == 1) {
count1++;
}
}
if(count4) {
cout << 150 << endl;
continue;
}
if(count3 && count2) {
cout << 40 << endl;
continue;
}
if(N == 5) {
sort(a.begin(), a.end());
bool flag = true;
for(int i = 1; i < N; i++) if(a[i] != a[i - 1] + 1) {
flag = false;
break;
}
if(flag) {
cout << 20 << endl;
continue;
}
}
if(count3) {
cout << 6 << endl;
continue;
}
if(count2 == 2) {
cout << 4 << endl;
continue;
}
if(count2 == 1) {
cout << 2 << endl;
continue;
}
cout << 1 << endl;
}
return 0;
} 第三题 模拟，怎么感觉样例有问题,只过了48%。。
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, m;
cin >> n >> m;
getchar();
string s;
getline(cin, s);
vector<string>words;
string word;
stringstream ss(s);
while(getline(ss, word, ' ')) {
if(!word.empty()) {
words.push_back(word);
}
}
vector<string>ans;
s = "";
for(int i = 0; i < words.size(); i++) {
if(s.empty()) {
s = words[i];
continue;
}
int next_len = 0;
if(isalpha(words[i].back())) {
next_len = s.size() + 1 + words[i].size();
} else {
next_len = s.size() + words[i].size();
}
if(next_len > n) {
if(next_len <= n + m) {
s.append(" " + words[i]);
ans.push_back(s);
s = "";
} else {
ans.push_back(s);
s = words[i];
}
} else {
s.append(" " + words[i]);
}
}
if(!s.empty()) ans.push_back(s);
cout << ans.size() << endl;
for(auto &i: ans) cout << i << endl;
return 0;
}
#include <bits/stdc++.h>
using namespace std;
int dir[4][2] = {{1, 0}, {-1, 0}, {0, 1}, {0, -1}};
int a[701][701];
bool vis[701][701];
struct Node {
int x, y, hour;
Node(int i, int j, int k): x(i), y(j), hour(k) {}
bool operator<(const Node &p) const {
return hour > p.hour;
}
};
int main() {
memset(vis, 0, sizeof(vis));
int n, m, x, y, z, w;
cin >> n >> m >> x >> y >> z >> w;
for(int i = 0; i < n; i++) {
for(int j = 0; j < m; j++) {
cin >> a[i][j];
}
}
--x, --y, --z, --w;
int nowH = 0;
priority_queue<Node>q;
q.emplace(Node(x, y, a[x][y]));//注意如果在原点，也要等到海面涨到该高度时才能运走！！
int ans = 0;
vis[x][y] = true;
while(!q.empty()) {
auto now = q.top();
q.pop();
if(now.x == z && now.y == w) {
ans = now.hour;
break;
}
for(int i = 0; i < 4; i++) {
int next_x = now.x + dir[i][0];
int next_y = now.y + dir[i][1];
if(next_x >= 0 && next_x < n && next_y >= 0 && next_y < m && !vis[next_x][next_y]) {
if(now.hour >= a[next_x][next_y]) {//当前时间下，水面早已经涨到这个高度了
q.emplace(Node(next_x, next_y, now.hour));
} else {//否则至少要等到a[next_x][next_y]时水面才能涨到该位置
q.emplace(Node(next_x, next_y, a[next_x][next_y]));
}
vis[next_x][next_y] = true;
}
}
}
cout << ans << endl;
return 0;
} 
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