9.14 荣耀笔试幸运抽奖
JS实现的,帮同学做的,原题没看完整,不知道对不对。
let xx = 'Nick', xxn = 0; // 嘉宾名和嘉宾的幸运值 let list = ['Tom', 'Jerry', 'Spike', 'Bob', 'Frank']; let obj = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5, 'f': 6, 'g': 7, 'h': 8, 'i': 9, 'j': 10, 'k': 11, 'l': 12, 'm': 13, 'n': 14, 'o': 15, 'p': 16, 'q': 17, 'r': 18, 's': 19, 't': 20, 'u': 21, 'v': 22, 'w': 23, 'x': 24, 'y': 25, 'z': 26} xx = xx.toLowerCase(); for (let i of xx) { xxn = xxn + obj[i]; } console.log('嘉宾的幸运值为:', xxn); console.log('抽奖人员名字及幸运值为:', list); let len = list.length; let lacky = [], pai = [], who; for (let i = 0; i < len; i++) { let n = 0; list[i] = list[i].toLowerCase(); for (let item of list[i]) { n = n + obj[item]; } lacky.push(n); } for (let j = 0; j < lacky.length; j++) { let m = Math.abs(lacky[j] - xxn); pai.push(m); if (pai[j] < pai[j - 1]) { who = list[j] } } console.log(lacky) console.log('跟嘉宾幸运值最接近的中奖者是', who, '!');