【牛客题霸每日一题】NC33 合并有序链表 题解
合并有序链表，利用两个双指针分别指向两个链表头部，每次比较两个指针指向结点的值，取较小的一个存入结果链表，代码如下：
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* };
*/
class Solution {
public:
/**
*
* @param l1 ListNode类
* @param l2 ListNode类
* @return ListNode类
*/
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
// write code here
ListNode *dummyHead = new ListNode(0);
ListNode *cur = dummyHead;
while(l1 && l2) {
if(l1->val < l2->val) {
cur->next = l1;
l1 = l1->next;
} else {
cur->next = l2;
l2 = l2->next;
}
cur = cur->next;
}
while(l1) {
cur->next = l1;
l1 = l1->next;
cur = cur->next;
}
while(l2) {
cur->next = l2;
l2 = l2->next;
cur = cur->next;
}
return dummyHead->next;
}
};
主管面要是真挂了，你黑化更彻底😂