第二题

class Solution:
    def string2(self , k , s ):
        a=[ord(i) for i in "qwertyuiopasdfghjklzxcvbnm"]
        b=[ord(i) for i in s]
        result=0
        for i in a:
            b.sort(key=lambda x:abs(i-x))
            current=0
            c=k
            for j in b:
                if c>=abs(i-j):
                    c-=abs(i-j)
                    current+=1
                else:
                    break
            result=max(result,current)
        return result