9.5 搜狗【测试】笔试题解
1. 换礼物,a,b,c任意两个可以换一个,求最大换取礼物
二分查找
class Solution: def numberofprize(self , a , b , c ): # write code here high = (a+b+c) * 2 // 3 low = 0 while low <= high: mid = (high + low) // 2 higher = 0 lower = 0 for letter in [a,b,c]: if letter >= mid: higher += letter - mid else: lower += mid - letter if higher == 2 * lower: return mid elif higher < 2 * lower: high = mid - 1 else: low = mid + 1 return high2. 建房子,要建一座房子宽度为t,已建房子xa,每两个分别表示房子中心和宽度,求建房子方法数
class Solution: def getHouses(self , t , xa ): # write code here n = len(xa) count = 2 temp = [] for i in range(0,n,2): tmp = [xa[i]-xa[i+1]/2, xa[i]+xa[i+1]/2] temp.append(tmp) for i in range(len(temp)-1): if temp[i+1][0] - temp[i][1] == t: count += 1 elif temp[i+1][0] - temp[i][1] > t: count += 2 return count3. 写测试用例,长度小于10的非空字符串,消除后结果不出现'ab'和'c'
abdcab d
dddd dddd
ababab NULL
acb NULL
aaabbb NULL
accccccbbb bb
dddccabccc ddd
aaaaabbbbb NULL
accccccccb NULL
adbadbadba adbadbadba
#笔试题目##搜狗#dddd dddd
ababab NULL
acb NULL
aaabbb NULL
accccccbbb bb
dddccabccc ddd
aaaaabbbbb NULL
accccccccb NULL
adbadbadba adbadbadba