度小满笔试题（Android岗位100%和64%）
求隔山打牛正确思路！！！
第一题：棋盘遍历：100%
public class one {
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
long n = read.nextLong();
long m = read.nextLong();
if(n == 1 || m == 1){
if(n == 1){
System.out.println(m - 1 + m - 1 );
}else{
System.out.println(n - 1 + n - 1);
}
}
else if(n % 2 == 0 || m % 2 == 0){
System.out.println(n*m);
}else{
System.out.println(n * m + 1);
}
}
} 第二题：隔山打牛：64%
public class two {
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int n = read.nextInt();
int[] num = new int[n+1];
for(int i = 1;i<=n;i++){
num[i] = read.nextInt();
}
int max;
int sum = 0;
for(int i=n;i>=1;i--){
if(num[i] > 0){
sum+=num[i];
//奇数的
if(i - 1 > 0 && (( i - 1) % 2 ) == 0){
num[i - 1] -= num[i];
num[(i - 1) / 2] -= num[i];
}else if(i != 1){ // 偶数的
num[ i / 2 ] -= num[i];
}
}
}
System.out.println(sum);
}
} 
