华为笔试

难道不是直接准备秋招？？😂

华为笔试不过，秋招就没面试机会了么？

我把题解思路写出来了 https://www.nowcoder.com/discuss/179895 可以参考下

我也一题没AC😭

今天的不是挺简单的吗

1. 枚举所有permutation，找出合法的最大时间 2. 把所有商品按成本排序，从成本最小的商品开始买，如果本次收益为正则购买，本钱加上本次收益，遇到本钱买不起的商品结束 3. 维护cpus和jobs两个list，均按降序排列，初始时cpus = [0] * m。每次cpus和jobs pop出最后一个元素cpu和job，cpu和job相加插入到cpus首位。到jobs为空停止。cpus[0]即为所求。

IN = [int(x) for x in input().replace('[', '').replace(']', '').split(',')] times = [] for a in range(6):     for b in range(6):         for c in range(6):             for d in range(6):                 for e in range(6):                     for f in range(6):                         if a != b and a != c and a != d and a != e and a != f and b != c and b != d and b != e and b != f and c != d and c != e and c != f and d != e and d != f and e != f:                             times.append([IN[a] * 10 + IN[b], IN[c] * 10 + IN[d], IN[e] * 10 + IN[f]]) res = [-1, -1, -1] for each in times:     hour = each[0]     m = each[1]     s = each[2]     if hour < 24 and m < 60 and s < 60:         if hour > res[0]:             res[0] = hour             res[1] = m             res[2] = s         elif hour == res[0] and m > res[1]:             res[0] = hour             res[1] = m             res[2] = s         elif hour == res[0] and m == res[1] and s > res[2]:             res[0] = hour             res[1] = m             res[2] = s if sum(res) == -3:     print("invalid") else:     print(str(res[0]).zfill(2) + ':' + str(res[1]).zfill(2) + ':' + str(res[2]).zfill(2))

a = [int(x) for x in input().split(',')] b = [int(x) for x in input().split(',')] c = int(input()) t = list(zip(a, b)) t.sort() for i in range(len(t)):     if t[i][0] > c:         break     if t[i][0] >= t[i][1]:         continue     c += t[i][1] - t[i][0] print(c)

m, n = [int(x) for x in input().split()] jobs = [int(x) for x in input().split()] jobs.sort(reverse=True) cpus = [0] * m while jobs: cpu = cpus.pop() job = jobs.pop() cpu = cpu + job cpus.insert(0, cpu) print(cpus[0])

5月还有笔试吗？