腾讯2019秋招软件开发笔试题解

第一题
static int cnt = 0;

static int[] prime = new int[1000006];

public static void main(String[] args) throws Exception {  Scanner in = new Scanner(System.in);  int n = in.nextInt();  prime(n);  long ans = 2;  for (int i = 0; i < cnt; i++) {  int p = prime[i];  long a = 1;  while (a * p <= n) {  a *= p;  }  long b = (n / a + 1) * a;  ans = Math.max(b, ans);  }  System.out.println(ans);
}
private static void prime(int maxnum) {  boolean[] notPrime = new boolean[maxnum+1];  notPrime[0] = notPrime[1] = true;  int i, j;  for (i = 2; i <= maxnum; i++) {  if (!notPrime[i]) {  prime[cnt++] = i;  for (j = i + i; j <= maxnum; j += i) {  notPrime[j] = true;  }  }  }
}
第二题
import java.util.*;

public class Main {  static boolean[][] isReach;  public static void main(String[] args) {  Scanner scan = new Scanner(System.in);  int n = scan.nextInt();  int m = scan.nextInt();  isReach = new boolean[n][n];  for (int i = 0; i < m; i++) {  isReach[scan.nextInt() - 1][scan.nextInt() - 1] = true;  }  for (int i = 0; i < n; i++) {  for (int j = 0; j < n; j++) {  if (i != j && isReach[i][j]) {  dfs(i, j, n);  }  }  }  int[][] count = new int[n][2];  for (int i = 0; i < n; i++) {  for (int j = 0; j < n; j++) {  if (isReach[i][j]) {  count[i][0]++;  count[j][1]++;  }  }  }  int res = 0;  for (int i = 0; i < n; i++) {  if (count[i][1] > count[i][0]) {  res++;  }  }  System.out.println(res);  }  public static void dfs(int begin, int end, int n) {  for (int i = 0; i < n; i++) {  if (i != end) {  if (isReach[end][i] && !isReach[begin][i] && begin != i) {  isReach[begin][i] = true;  dfs(begin, i, n);  }  }  }  }
}
第三题
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in.hasNextInt()) {//注意while处理多个case
            int t = in.nextInt();
            for(int i = 0; i < t; i++) {  int A = in.nextInt();  int B = in.nextInt();  int C = in.nextInt();  boolean flag = false;  for(int j = 1; j <= 100; j++) {  if(j * A % B == C) {  flag = true;  break;  }  }  if(flag) {  System.out.println("YES");  } else {  System.out.println("NO");  }   }
        }
    }

#秋招##腾讯##题解#
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