华为5月3日笔试

分享下代码吧

第二题后来改样例和边界了？？喵喵喵？

第一题AC int main() { string str; cin >>str; int a[15]={0}; stack sta; for(int i=0;i<str.length();i++) { if(int(a[str[i]-'0'])==0) { sta.push(str[i]-'0'); a[str[i]-'0']=1; } else { continue; } } if(sta.top()==0) { sta.pop(); } else { cout <<sta.top(); sta.pop(); } while(!sta.empty()) { cout <<sta.top(); sta.pop(); } }

第二题蜜汁50% 第三题蜜汁45.45%

第二题蜜汁诡异，求代码

太坑爹了，数据范围给错，真的是搞人，怀疑人生了。。。

so，第二题到底改了什么？

感觉比四月份那套题坑很多

为啥我4月份就笔试了

 1 2 AC  2没AC 就一直做着  3就0% 要跪了···········

我之前也错过了笔试 请问怎么联系能再申请笔试

求第三题AC代码

import os def int2set(array):      out1 = []     out2 = ""     for i in range(len(array)):         if array[i] not in out1:             out1.append(array[i])           for i in range(len(out1)-1 , -1 , -1):         if i == len(out1)-1 and out1[i] == '0' :             continue         else:             out2 = out2 + str(out1[i])     return out2 s = list("98766730") a = int2set(array = s) print (a)

import os #数据已改 (-170,-1000),(0,700),(40,940), (300, 2500),(550,7500) def calnum (x1, y1, x2, y2, t):     return int( ((y2-y1)/(x2-x1)) * (t - x1) + y1 ) t =100 x1 , x2 = 0, 0 y1 , y2 = 0, 0      while (True):     t = int( input())     if t < -400:         print("-400")     if t > 1000:         print("1000")     if t < -170:         x1 = -170         y1 = -1000         x2 = 0         y2 = 700         print(calnum(x1, y1, x2, y2, t))     elif t < 0:         x1 = -170         y1 = -1000         x2 = 0         y2 = 700         print(calnum(x1, y1, x2, y2, t))     elif t < 40:         x1 = 0         y1 = 700         x2 = 40         y2 = 940         print(calnum(x1, y1, x2, y2, t))     elif t < 300:         x1 = 40         y1 = 940         x2 = 300         y2 = 2500         print(calnum(x1, y1, x2, y2, t))     elif t < 550:         x1 = 300         y1 = 2500         x2 = 550         y2 = 7500         print(calnum(x1, y1, x2, y2, t))     else:         x1 = 300         y1 = 2500         x2 = 550         y2 = 7500         print(calnum(x1, y1, x2, y2, t))