小米字符串第一题,状态机思路
这题用状态机比较好解决,代码看起来清晰很多
#include <iostream>
#include <vector>
#include <string>
#include <list>
#include <queue>
#include <unordered_map>
#include <algorithm>
using namespace std;
string to_upper(string& s) {
for (auto& c : s) {
c = toupper(c);
}
return s;
}
int main() {
string s;
while (cin >> s) {
int state = 0;
vector<string> v;
int i, j;
for (i = 0, j = 0; j < s.length(); j++) {
if (s[j] == '.') {
state = 0;
v.push_back(s.substr(i, j - i));
i = j + 1;
}
else if (isupper(s[j])) {
if (state == 0) state = 1;
else if (state == 1) state = 3;
else if (state == 2 || state == 4 || state == 5) {
v.push_back(s.substr(i, j - i));
state = 1;
i = j;
}
}
else if (islower(s[j])) {
if (state == 0) state = 5;
else if (state == 1) state = 2;
else if (state == 3) {
v.push_back(s.substr(i, j - i - 1));
state = 2;
i = j - 1;
}
else if (state == 4) {
v.push_back(s.substr(i, j - i));
state = 5;
i = j;
}
}
else if (isdigit(s[j])) {
if (state == 0) state = 4;
else if (state != 4) {
v.push_back(s.substr(i, j - i));
state = 4;
i = j;
}
}
}
if (state != 0) v.push_back(s.substr(i, j - i));
string res = "_";
for (auto& e : v) {
res += to_upper(e), res += "_";
}
cout << res << endl;
}
return 0;
}#小米#