京东笔试编程题，重叠子串和括弧
京东笔试，第一条关于重叠子串的题目public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String s = in.next();
char[] str = s.toCharArray();
int index = -1;
for (int i = 1; i < str.length; i++) {
boolean overlap = true;
for (int j = 0; i+j < str.length; j++) {
if (str[i+j] != str[j]) {
overlap = false;
break;
}
}
if (overlap) {
index = i;
break;
}
}
String res = null;
if (index != -1) {
res = s + s.substring(str.length - index);
}
else {
res = s + s;
}
System.out.println(res);
}
第二道 关于括弧的题目
public class Second {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String line = in.nextLine();
HashMap<String, Integer> map = new HashMap<>();
int time = findTime(line, map);
System.out.println(time);
}
public static int findTime(String line, HashMap<String, Integer> map) {
if (line.isEmpty()) {
return 1;
}
if (map.containsKey(line)) {
return map.get(line);
}
int res = 0;
for (int i = 1; i < line.length(); i++) {
if (line.charAt(i) == ')') {
String left = null;
if (i == 1) {
left = line.substring(2);
}
else {
left = line.substring(1, i) + line.substring(i+1);
}
if (isLegal(left)) {
res += findTime(left, map);
}
}
}
map.put(line, res);
return res;
}
public static boolean isLegal(String str) {
int l = 0, r = 0;
for (int i = 0; i < str.length(); i++) {
if (str.charAt(i) == '(') {
l++;
}
else {
r++;
}
if (r > l) {
return false;
}
}
return true;
}
}
#京东#
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