拼多多第一题，按照要求输出了，结果只有40%

这个是我的代码, 也不知道怎么错. 同求高人指点. #include <iostream> #include <algorithm> #include <set> #include <vector> #include <stack> #include <set> #include <list> #include <bitset> #include <cstring> using namespace std; struct Bear { int fight; int hungry; }; int find_h(vector<Bear>& bears) { int i = 0; int h = -1; int idx = -1; while (i < bears.size()) { if (bears[i].hungry <= 0) { i++; continue; } if (h < bears[i].hungry) { h = bears[i].hungry; idx = i; } i++; } return idx; } void bear_eat(vector<Bear> &bears, int idx, vector<int>& suguars) { for (int i = suguars.size() - 1; i >= 0; i--) { if (suguars[i] == -1) continue; else if( suguars[i] > bears[idx].hungry) continue; else { bears[idx].hungry -= suguars[i]; suguars[i] = -1; break; } } } bool can_eat(vector<Bear> &bears, vector<int> &suguars) { vector<int> hs; for (int i = 0; i < bears.size(); i++) { if (bears[i].hungry > 0) { hs.push_back(bears[i].hungry); } } for (int i = 0; i < suguars.size(); i++) { if (suguars[i] > 0) for (auto& h: hs) if (suguars[i] <= h) return true; } return false; } void hdl(vector<Bear>& bears, vector<int>& suguars) { sort(suguars.begin(), suguars.end()); while (can_eat(bears, suguars)) { int most_h = find_h(bears); if (most_h == -1) break; bear_eat(bears, most_h, suguars); } } int main() { int n, m; cin >> n >> m; vector<int> suguars; for (int i = 0; i < m; i++) { int tmp; cin >> tmp; suguars.push_back(tmp); } vector<Bear> bears; for (int i = 0; i < n; i++) { int f = 0, h = 0; cin >> f >> h; bears.push_back({f, h}); } hdl(bears, suguars); for (int i = 0; i < bears.size() - 1; i++) cout << bears[i].hungry << endl; cout << bears[bears.size() - 1].hungry; return 0; }

#include<iostream> #include<vector> #include<algorithm> using namespace std; bool cmp(int a, int b) { return a > b; } bool cmp1(vector<int>a, vector<int>b) { return a[0] > b[0]; } int main() { int n, m; while (cin >> n >> m) { vector<int>a(m); //糖的能量值 for (int i = 0; i < m; i++) cin >> a[i]; vector<vector<int>>b(n,vector<int>(2)); //存储小熊的战斗力和饥饿值 for (int i = 0; i < n; i++) { for (int j = 0; j < 2; j++) { cin >> b[i][j]; } } sort(a.begin(), a.end(),cmp); vector<vector<int>>b1(b.begin(), b.end()); sort(b1.begin(), b1.end(), cmp1); vector<int>flag(m, 0); vector<int>res(n,0); //存储小熊剩余饥饿值 for (int i = 0; i < n; i++) { int j = 0; int tmp = b1[i][1]; while (j < m) { if (a[j] <= tmp && !flag[j]) { tmp = tmp - a[j]; flag[j] = 1; } j++; } res[i]=tmp; } for (int i = 0; i < n; i++) //输出 { int t = b[i][0]; for (int j = 0; j < n; j++) { if (b[j][0] == t) { cout << res[j] << endl; break; } } } } } 不知道为什么只通过了40%，思路应该没问题，我觉得应该是超时了。求大神指点。

要按照原来输入小熊的顺序 输出相应的饥饿值

用例中提供的数据是排序了的

你是没按要求输出，题目要求按给的熊的顺序而不是排序后的熊的顺序

妹子刷题量惊人啊

话说你sort的写法编译能通过？我也这么写的编译就过不去，只好手撸个冒泡排序。。。

用sort（begin，end，compare），排序两次。第一次按照战斗力排序，第二次按照编号排序。