360笔试最后一题，依据均匀分布求a的值

＃include<iostream>

using namespace std;

void getWinNumber(int n, int b){
    int result = 0;
    float middle = static_cast<float >(n+1)/2;
    if (b > middle){
        result = b-1;
    }
    else if (b < middle){
        result = b+1;
    }
    else
        result = b-1;
    cout << result << endl;
} int main(){
    int n, b ;
    while (cin >> n >> b){
        getWinNumber(n,b);
    }
    return 0;
}