一个用C语言写的迷你版2048游戏,只有487个字符
Jay Chan 用 C 语言写的一个迷你版 2048 游戏,只有 487 个字符。来围观吧:
M[16],X=16,W,k;main(){T(system("stty cbreak") );puts(W&1?"WIN":"LOSE");}K[]={2,3,1};s(f,d,i ,j,l,P){for(i=4;i--;)for(j=k=l=0;k<4;)j<4?P=M [w(d,i,j++)],W|=P>>11,l*P&&(f?M[w(d,i,k)]=l<< (l==P):0,k++),l=l?P?l-P?P:0:l:P:(f?M[w(d,i,k) ]=l:0,++k,W|=2*!l,l=0);}w(d,i,j){return d?w(d -1,j,3-i):4*i+j;}T(i){for(i=X+rand()%X;M[i%X] *i;i--);i?M[i%X]=2<<rand()%2:0;for(W=i=0;i<4; )s(0,i++);for(i=X,puts("\e[2J\e[H");i--;i%4|| puts(""))printf(M[i]?"%4d|":" |",M[i]);W-2 ||read(0,&k,3)|T(s (1,K[(k>>X)%4]));}//[2048]
下面是其他热心网友给上面程序加了注解:
// Original file by Jay Chan: // https://gist.github.com/justecorruptio/9967738 #include <stdio.h> #define GRID_LEN 16 int M[GRID_LEN]; int X = GRID_LEN; int W; int k; int K[] = {2, 3, 1}; s(f, d, i, j, l, P) { for(i = 4; i--;) { for(j = k = l = 0; k < 4;) { if(j < 4) { P = M[w(d, i, j++)]; W |= P >> 11; l * P && (f ? M[w(d, i, k)] = l << (l == P) : 0, k++); l = l ? (P ? (l-P ? P : 0) : l) : P; } else { f ? M[ w(d, i, k) ] = l : 0; ++k; W |= 2 * !l; l = 0; } } } } int w(d, i, j) { // Decrements until d reaches 0 // Recursive function if(d <= 0) { return 4 * i + j; } return w(d - 1, j, 3 - i); } T(i) { for(i = X + rand() % X; M[i % X] * i; i--); i ? M[i % X] = 2 << rand() % 2: 0; for(W = i = 0; i < 4; i++) { s(0, i); } // Prints the tiles onto the terminal for(i = X, puts("\e[2J\e[H"); i--; i % 4 || puts("")) { printf(M[i] ? "%4d|":" |", M[i]); } // Read input from keyboard W - 2 || read(0, &k, 3) | T(s (1, K[(k >> X) % 4])); } int main() { // Uses stty to clear the screen in preparation for the game T(system("stty cbreak")); // Game has finished by this point // If win, display "WIN". Otherwise, display "LOSE". puts(W & 1 ? "WIN" : "LOSE"); return 0; } //[2048]
转自伯乐在线