题解 | #[NOIP2008]笨小猴#

words = input()
lis = []
for i in words:
    lis.append([i, words.count(i)])  # 将字母及对应的出现次数放到嵌套列表里排序
lis.sort(key=lambda x: x[1])
main = lis[-1][1] - lis[0][1]  # 取左右两个进行差值计算
if main > 1:  # 判断差值是否为质数
    for i in range(2, main):
        if (main % i) == 0:
            print("No Answer")
            print("0")
            break
    else:
        print("Lucky Word")
        print(main)
else:
    print("No Answer")
    print("0")

唯一考点是判断质数