多线程打印之Semphore

package com.zhang.reflection.面试.多线程打印;
import java.util.concurrent.Semaphore;
public class Semaphore实现 {
    private int times;
    private Semaphore semaphore1=new Semaphore(1);
    private Semaphore semaphore2=new Semaphore(0);
    private Semaphore semaphore3=new Semaphore(0);
    public Semaphore实现(int times){
        this.times=times;
    }
    public static void main(String[] args) {
        Semaphore实现 a=new Semaphore实现(10);
        new Thread(()->a.printA()).start();
        new Thread(()->a.printB()).start();
        new Thread(()->a.printC()).start();
    }
    public void printA() {
        try{
            print("A",semaphore1,semaphore2);
        }catch(Exception e){
            e.printStackTrace();
        }
    }
    public void printB() {
        try{
            print("B",semaphore2,semaphore3);
        }catch(Exception e){
            e.printStackTrace();
        }
    }
    public void printC() {
        try{
            print("C",semaphore3,semaphore1);
        }catch(Exception e){
            e.printStackTrace();
        }
    }
    public void print(String name,Semaphore current,Semaphore next) throws InterruptedException {
        for(int i=1;i<=times;i++){
            current.acquire(1);
            System.out.println(name);
            next.release();
        }
    }
}

package test;
import java.util.concurrent.Semaphore;
public class Main{
    private static Semaphore s1=new Semaphore(1);
    private static Semaphore s2=new Semaphore(1);
    private static Semaphore s3=new Semaphore(1);
    public static void PrintABC(Semaphore cur,Semaphore next){
        for(int i=1;i<=10;i++){
            try{
                cur.acquire();
                System.out.print(Thread.currentThread().getName());
                next.release();
            }catch (Exception e){
                e.printStackTrace();
            }
        }
    }
    public static void main(String[] args) {
        try{
            s2.acquire();
            s3.acquire();
        }catch (Exception e){
            e.printStackTrace();
        }
        new Thread(()->PrintABC(s1,s2),"A").start();
        new Thread(()->PrintABC(s2,s3),"B").start();
        new Thread(()->PrintABC(s3,s1),"C").start();
    }
}