题解 | #字符串合并处理#

字符串合并处理

http://www.nowcoder.com/practice/d3d8e23870584782b3dd48f26cb39c8f

a=list(input())

a.remove(' ')

b=[]

c=[]

for i in range(len(a)):

if i%2==0:
    b[i:]=a[i]

for i in range(len(a)):

if i%2!=0:
    c[i:]=a[i]

b.sort()

c.sort()

for i in range(len(b)):

a[i*2]=b[i]

for i in range(len(c)):

a[i*2+1]=c[i]

for i in range(len(a)):

if a[i] in ['a','b','c','d','e','f','A','B','C','D','E','F'] or a[i] in ['1','2','3','4','5','6','7','8','9']:
    a[i]=int('0x'+str(a[i]),16)
    d1=a[i]//8
    d2=(a[i]-d1*8)//4
    d3=(a[i]-d1*8-d2*4)//2
    d4=a[i]-d1*8-d2*4-d3*2
    a[i]=d4*8+d3*4+d2*2+d1
    a[i]=hex(a[i])[-1].upper()

a=''.join(a)

print(a)

奇奇怪怪的解题成功∧…∧

全部评论

相关推荐

totoroyyw:千年老妖😂
投递华为等公司10个岗位
点赞 评论 收藏
分享
评论
点赞
收藏
分享
牛客网
牛客企业服务