题解 | #尼科彻斯定理#

def sunmNumber(n): L1=[] L2 =[] L3=[] if n ==1: return print(1) else: for i in range(1,n**3,2): L1.append(i) #print(L1)

    for j in range(len(L1)):
        L2=L1[j:j+n]
        #print(L2)
        if sum(L2)==n**3:
            L3=L1[j:j + n]
            #print(L3)

    return print(' '.join(str(x) for x in L3))

while True: try: n = int(input()) s =sunmNumber(n) except: break