题解 | #矩阵的最小路径和#

矩阵的最小路径和

http://www.nowcoder.com/practice/38ae72379d42471db1c537914b06d48e

dp[i][j]表示到位置i,j的最小路径和

import java.util.*;

public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int m = sc.nextInt();
        int[][] nums = new int[n][m];
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                nums[i][j] = sc.nextInt();
            }
        }
        int[][] dp = new int[n][m];
        dp[0][0] = nums[0][0];
        for (int i = 1; i < m; i++) {
            dp[0][i] = dp[0][i - 1] + nums[0][i]; 
        }
        for (int i = 1; i < n; i++) {
            dp[i][0] = dp[i - 1][0] + nums[i][0];
        }
        for (int i = 1; i < n; i++) {
            for (int j = 1; j < m; j++) {
                dp[i][j] = Math.min(dp[i][j - 1] + nums[i][j], dp[i - 1][j] + nums[i][j]);
            }
        }
        System.out.println(dp[n - 1][m - 1]);
    }
}
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