题解 | #公共子串计算#
公共子串计算
http://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
s1 =input()
s2 = input()
if len(s2)<len(s1):
s1, s2 = s2, s1
equal = []
for i in range(len(s1)):
for j in range(i, len(s2)):
if s1[i:j] in s2:
equal.append(len(s1[i:j]))
print(max(equal))
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