题解 | #密码强度等级#

思路

1. 按照题目一步一步分析编写代码
2. 统计输出结果

Answer

#include<stdio.h>
#include<string.h>

int main() {
    char str[300];
    int score = 0;
    scanf("%s",str);
    int len = strlen(str);
    //长度
    if (len <= 4) {
        score += 5;
    } else if (len <= 7) {
        score += 10;
    } else if (len >= 8) {
        score += 25;
    }
    //字母
    int flg_a = 0, flg_A = 0;
    int num_cnt = 0;
    int symbol = 0;
    for (int i = 0; i < len; i++) {
        if (str[i] >= 'a' && str[i] <= 'z') {
            flg_a = 1;
        } else if (str[i] >= 'A' && str[i] <= 'Z') {
            flg_A = 1;
        } else if (str[i] >= '0' && str[i] <= '9') {
            num_cnt++;
        } else {
            symbol++;
        }
    }
    if ((flg_A == 0) && (flg_a == 0)) {
        score += 0;
    } else if ((flg_A == 1) && (flg_a == 1)) {
        score += 20;
    } else {
        score += 10;
    }
    //数字
    if (num_cnt <= 0) {
        score += 0;
    } else if (num_cnt == 1) {
        score += 10;
    } else if (num_cnt > 1) {
        score += 20;
    }
    //符号
    if (symbol <= 0) {
        score += 0;
    } else if (symbol == 1) {
        score += 10;
    } else if (symbol > 1) {
        score += 25;
    }
    //奖励
    int result = 0;
    if (((flg_A == 1) || (flg_a == 1)) && (num_cnt >= 1)) {
        result = 2;
    }
    if (((flg_A == 1) || (flg_a == 1)) && (num_cnt >= 1) && (symbol >= 1)) {
        result = 3;
    }
    if ((flg_A == 1) && (flg_a == 1) && (num_cnt >= 1) && (symbol >= 1)) {
        result = 5;
    }
    if ((score + result) >= 90) {
        printf("VERY_SECURE\n");
    }else if ((score + result) >= 80) {
        printf("SECURE\n");
    }else if ((score + result) >= 70) {
        printf("VERY_STRONG\n");
    }else if ((score + result) >= 60) {
        printf("STRONG\n");
    }else if ((score + result) >= 50) {
        printf("AVERAGE\n");
    }else if ((score + result) >= 25) {
        printf("WEAK\n");
    }else if ((score + result) >= 0) {
        printf("VERY_WEAK\n");
    }

    return 0;
}