282A. Bit++
282A. Bit++
- time limit per test1 second
- memory limit per test256 megabytes
- inputstandard input
- outputstandard output
The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.
Bitland的经典编程语言是Bit++。这种语言是如此奇特和复杂。
The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:
这种语言非常独特,因为它只有一个变量,叫做x。此外,有两种操作:
- Operation ++ increases the value of variable x by 1.
Operation++将变量x的值增加1。
- Operation -- decreases the value of variable x by 1.
操作--将变量x的值减少1。
A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.
Bit++语言中的语句是一个序列,只包含一个操作和一个变量x。该语句不带空格,即只能包含字符“+”、“-”、“x”。执行语句意味着应用它包含的操作。
A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.
Bit++中的程序是一系列语句,每个语句都需要执行。执行一个程序意味着执行它包含的所有语句。
You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).
你得到了一个用Bit++语言编写的程序。x的初始值为0。执行该程序并找到其最终值(执行该程序时变量的值)。
Input
The first line contains a single integer n (1 ≤ n ≤ 150) — the number of statements in the programme.
第一行包含一个整数n(1 ≤ n ≤ 150)-节目中的发言次数。
Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.
接下来的n行分别包含一条语句。每个语句只包含一个运算(++或--)和一个变量x(表示为字母«x»)。因此,不存在空语句。操作和变量可以按任意顺序写入。
Output
Print a single integer — the final value of x.
打印一个整数——x的最终值。
Examples
input1
1
++X
output1
1
input2
2
X++
--X
output2
0
Solution
考虑到X++或者++X在第二位上都是+,X--或者--X在第二位上都是-,因此只要对第二位进行判断为+还是-即可
Code
#include <iostream>
using namespace std;
//282A. Bit++
int main() {
int n = 0;//n:发言次数
cin >> n;
int x =0;//x:x的最终值
for(int i = 0;i < n;i++){
string str;
cin >> str;
if(str[1]=='+'){
x++;
}else{
x--;
}
}
cout << x << endl;
return 0;
}
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