题解 | #二维数组操作#

• 思路：为了避免判断代码冗余让人心态炸裂，使用mu和nu代表行和列的下标范围

while True:
    try:
        m, n = map(int, input().split(" "))
        x1, y1, x2, y2 = map(int, input().split(" "))
        x, y = int(input()), int(input())
        x3, y3 = map(int, input().split(" "))
        mu, nu = [i for i in range(m)], [i for i in range(n)]
        print(0 if (0 <= m <= 9) and (0 <= n <= 9) else -1)
        print(0 if (x1 in mu) and (x2 in mu) and (y1 in nu) and (y2 in nu) else -1)
        print(0 if (m < 9) and (x in mu) else -1)
        print(0 if (n < 9) and (y in nu) else -1)
        print(0 if (x3 in mu) and (y3 in nu) else - 1)
    except:
        break