题解 | #时间转换#
时间转换
http://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include<stdio.h> int main () { int secinds = 0; int a = 0; scanf("%d",&secinds); a = secinds / 3600; printf("%d ",a); int b = (secinds % 3600) / 60; printf("%d ",b); int c = secinds % 3660 % 60; printf("%d",c); return 0; }
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