题解 | #牛牛的计划#
牛牛的计划
http://www.nowcoder.com/practice/cf956ceef9f84f7393a0b7284fdbf95a
#include <stdio.h> int main(){ int y,m,d; int y1,m1,d1; scanf("%d %d %d\n%d %d %d",&y,&m,&d,&y1,&m1,&d1); if(y==y1&&m==m1&&d<=d1){ printf("yes"); } else if(y1>y){ printf("yes"); } else { printf("no"); } }