题解 | #人民币转换#
人民币转换
http://www.nowcoder.com/practice/00ffd656b9604d1998e966d555005a4b
各种if语句应接不暇
x = '零、壹、贰、叁、肆、伍、陆、柒、捌、玖'
xi = '壹、贰、叁、肆、伍、陆、柒、捌、玖'
xi = xi.split('、')
y = {}
for n, i in enumerate(x.split('、')):
y[str(n)] = i
ii = '123'
def get_bai(ii):
if len(ii) == 1:
u = y[ii]
elif len(ii) == 2:
u = y[ii[0]]+'拾'+y[ii[1]]
elif len(ii) == 3:
u = y[ii[0]]+'佰'+y[ii[1]]+'拾'+y[ii[2]]
elif len(ii) == 4:
u = y[ii[0]]+'仟'+y[ii[1]]+'佰'+y[ii[2]]+'拾'+y[ii[3]]
else:
return '零'
ul = list(u)
def get_l(ul):
for n, i in enumerate(ul):
if n+1 == len(ul): # 如果零后面没有了 则删除自己。
ul.pop(n)
return ul
elif i == '零' and ul[n+1] not in xi: # 如果零后面有单位或零，则删除后面的。
ul.pop(n+1)
return get_l(ul)
return ul
if '零' in ul:
get_l(ul)
return ''.join(ul)
def get_jf(ii):
res = y[ii[0]]+'角'+y[ii[1]]+'分'
if ii[1] == '0':
res = res[0:-2]
elif ii[0] == '0':
res = res[-2:]
return res
def get_all(ii):
if len(ii) <= 4:
res = get_bai(ii)
if len(res) == 3 and res[0] == '壹':
res = res[1:]
return res
elif 4 < len(ii) < 9:
res1 = get_bai(ii[0:-4])
if len(res1) == 3 and res1[0] == '壹':
res1 = res1[1:]
res2 = get_bai(ii[-4:])
return res1+'万'+res2
while True:
try:
l = list(map(str, input().split('.')))
if len(l) == 1:
res = get_all(l[0])
print('人民币'+res+'元整')
else:
res = get_all(l[0])
if res:
print('人民币'+res+'元' + get_jf(l[1]) )
else:
print('人民币' +get_jf(l[1]))
except EOFError:
break
