题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
http://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
钻个空子，大佬勿喷
while True:
try :
n = int(input().strip())
m = input().strip().split()
k = int(input().strip())
m.append('0')
print(''.join(i for i in m[::-1][k]))
except :
break
