题解 | #百钱买百鸡问题#
百钱买百鸡问题
http://www.nowcoder.com/practice/74c493f094304ea2bda37d0dc40dc85b
# -*-coding:utf-8-*-
def Buycheck(num):
jiwen = 5
muji = 3
xiaoji = 1/3
for i in range(0,20):
for j in range(0,33):
for k in range(0,100):
if i+j+k == 100 and i*jiwen+j*muji+k*xiaoji==100:
print("%d %d %d" %(i,j,k))
while True:
try:
input_m = input()
if input_m.isdigit():
Buycheck(input_m)
else:
break
except:
break