C++：存在虚函数的父类和派生类的指针指向的内存探讨

本文讨论下面这种情况，指针指向的东西是啥：
（如果Base是父类，Derived是派生类，那么Base* (Derived)这种指针究竟指向了啥？
1.定义代码：

#include "iostream"
using namespace std;


class Base1{
   
public:
    Base1():base1_1(11){
   }
    int base1_1;
    virtual void base1_fun1(){
   
        cout<<"base_fun1"<<endl;
    }
};

class Base2{
   
public:
    virtual void base2_fun1(){
   
        cout<<"base2_fun1"<<endl;
    }
};

class Base3{
   
public:
    virtual void base3_fun1(){
   
        cout<<"base_fun3"<<endl;
    }
};

class Derived:public Base1,public Base2,public Base3{
   
public:
    virtual void derived_fun1(){
   
        cout<<"derived_fun1"<<endl;
    }
    virtual void base1_fun1(){
   
        cout<<"derived_fun1"<<endl;
    }
};

2.main代码：

int main(){
   
    Derived d1;
    Base1* ptr1 = &d1;
    Base2* ptr2 = &d1;
    Base3* ptr3 = &d1;
    Derived* ptr4 = &d1;

    ptr1->base1_fun1();//1

    ptr3->base3_fun1();

    ptr4->base1_fun1();
    ptr4->base3_fun1();
    ptr4->derived_fun1();

    cout<<&d1<<" ";
    cout<<ptr1<<" ";
    cout<<ptr2<<" ";
    cout<<ptr3<<" ";
    cout<<ptr4<<" ";
    cout<<endl;
}

3.结果

4.结论

Derived d1;
Base1* ptr1 = &d1;
Base2* ptr2 = &d1;
Base3* ptr3 = &d1;
Derived* ptr4 = &d1;

我觉得种种迹象表明
Base1指针指向派生类d1的话，实际上是只会看到Base1的虚函数，也只会看到Base1的构造函数出来的东西。
Derived指针的话，啥都能看到。