题解 | #数组元素反转#

using namespace std;

int main() {

    int arr[6] = { 0 };

    int len = sizeof(arr) / sizeof(int);
    
    for (int i = 0; i < len; i++) {
        cin >> arr[i];
    }

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << arr[i] << "]" << endl;
            break;
        }
        cout << arr[i] << ", ";
    }

    // write your code here......
    int newArr[6] = {NULL};
//     int mid = len / 2;
    for(int i = 0;i<=len;i++){
        newArr[i] = arr[len- i -1];    //将旧数组的倒序复制给新数组
    }
    

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << newArr[i] << "]" << endl;
            break;
        }
        cout << newArr[i] << ", ";
    }

    return 0;
}