题解 | #扑克牌大小#
扑克牌大小
http://www.nowcoder.com/practice/d290db02bacc4c40965ac31d16b1c3eb
插播一个反面教材
能做出来但是考虑复杂了
all_pic = '3 4 5 6 7 8 9 10 J Q K A 2 joker JOKER' input_dict = {} for n, i in enumerate(all_pic.split()): if i == 'joker': input_dict[i] = 100 elif i == 'JOKER': input_dict[i] = 200 else: input_dict[i] = n def get_ll(input_list): if len(input_list) == 1: return 0 # 单 elif len(input_list) == 2 and 'joker' not in input_list: return 1 # 对子 elif len(input_list) == 3: return 2 # 三不带 elif len(input_list) == 4: return 3 # 四炸 elif len(input_list) == 5: return 4 # 顺子 elif len(input_list) == 2 and 'joker' in input_list: return 5 # 王炸 else: return False def get_num(input_list): num_list = [input_dict[i] for i in input_list] return sum(num_list) def get_4num(input_list): num_list = [input_dict[i] for i in input_list] return sum(num_list) + 1 while True: try: input_res = input().split('-') left_input = input_res[0].split() right_input = input_res[1].split() left_n = 0 right_n = 0 if get_ll(left_input) == 5&nbs***bsp;get_ll(right_input) == 5: if get_ll(left_input) == 5: print(' '.join(left_input)) elif get_ll(right_input) == 5: print(' '.join(right_input)) elif get_ll(left_input) == 3&nbs***bsp;get_ll(right_input) == 3: if get_ll(left_input) == 3 and get_ll(right_input) != 3: print(' '.join(left_input)) elif get_ll(right_input) == 3 and get_ll(left_input) != 3: print(' '.join(right_input)) elif get_ll(right_input) == 3 and get_ll(left_input) == 3: if get_num(left_input) > get_num(right_input): print(' '.join(left_input)) elif get_num(left_input) < get_num(right_input): print(' '.join(right_input)) elif get_ll(left_input) != get_ll(right_input): print('ERROR') elif get_num(left_input) > get_num(right_input): print(' '.join(left_input)) elif get_num(left_input) < get_num(right_input): print(' '.join(right_input)) else: print('ERROR') except EOFError: break