刷题记录

1.回文数启发

def is_palindrome(n):
    return str(n)==str(n)[::-1]

字符串的切片操作

切片博客链接

s = 'ABCDLSESRF'

s1 = s[0:5:2]
print(s1)	# 输出结果为‘ACL’

s2 = s[4:0:-1]	# 此操作表示从0到4，倒着切片
print(s2)	# 输出结果为‘LDCB’

s3 = s[3::-1]
print(s3)	# 输出结果为‘DCBA’

s4 = s[3::-2]
print(s4)	# 输出结果为‘DB’

s5 = s[::-1]
print(s5)	# 输出结果为‘FRSESLDCBA’

s6 = s[-1::-1]
print(s6)	# 输出结果为‘FRSESLDCBA’