题解 | #skew数#
skew数
http://www.nowcoder.com/practice/5928127cc6604129923346e955e75984
#include <stdio.h>
#include <string.h>
#include <math.h>
#define MAX 32
int main(void)
{
char s[MAX];
while (scanf("%s", s) != EOF)
{
long answr = 0;
int n = strlen(s);
for (int i = 0; i < n; i++)
{
// printf("%d ", s[i] - '0');
answr += (s[i] - '0') * (pow(2, n - i) - 1);
}
// printf("\n");
printf("%ld\n", answr);
}
return 0;
}
