题解 | #求最大连续bit数#

def ten2two(ten):
    result = ""
    while ten != 0:
        result = str(ten % 2) + result
        ten = ten // 2
    return result


while True:
    try:
        n = int(input())
        res = list(str(ten2two(n)))
        td = []
        x = 0
        for n, i in enumerate(res):
            if i == '1':
                x += 1
                if n == len(res)-1:
                    td.append(x)
            else:
                if x != 0:
                    td.append(x)
                x = 0

        if td:
            print(max(td))
        else:
            print(0)
    except EOFError:
        break