题解 | #旋转数组的最小数字#
旋转数组的最小数字
http://www.nowcoder.com/practice/9f3231a991af4f55b95579b44b7a01ba
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param rotateArray int整型一维数组
# @return int整型
#
class Solution:
def minNumberInRotateArray(self , rotateArray: List[int]) -> int:
# write code here
if len(rotateArray)==0:return None
if len(rotateArray)==1:return rotateArray[0]
res=rotateArray[0]
for i in range(len(rotateArray)):
if rotateArray[i] <res:
res=rotateArray[i]
return res