【十二题解】 | #尼科彻斯定理#

#include<stdio.h>

int main(){

int number;
while(scanf("%d", &number) != EOF){
    int pinfang = number*number;
    int start;
    if (number%2 == 0){
        start = pinfang-number+1;
    }
    else{
        start = pinfang - number/2*2;
    }
    for(int i=0; i<number; i++){
        printf("%d", start+i*2);
        if(i!=number-1)printf("+");
    }
    printf("\n");
}

}