题解 | #从单向链表中删除指定值的节点#

def findIndex(c):
    index=0
    for num in link:
        if num==c:
            return index
        else :
            index+=1

while True:
    try :
        s=input().split()
        mount=s[0]
        head=s[1]
        delit=s[-1]
        s=s[2:-1]
        p=[]
        #print(s)
        link=[]
        for i in range(0,len(s),2):
            p.append((s[i],s[i+1]))
        link.append(p[0][1])
        for item in p:
            idx=findIndex(item[1])
            link.insert(idx+1,item[0])
        
        rg=len(link)
        for i in range(rg):
            if link[i]==delit:
                link.pop(i)
                break
        #link=list(map(int, link))
        print(" ".join(link))
       # print(link)
        
        
    except:
        break